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vovikov84 [41]
3 years ago
12

NEED ASAP whats the value of x

Mathematics
2 answers:
Sidana [21]3 years ago
8 0

Answer:


Step-by-step explanation:you would multiply all the side then I would divide how many sides there are


Juliette [100K]3 years ago
6 0

A straight line is 180°. So:

∠QRT + ∠TRS = 180°    [outside ∠R + inside ∠R = 180]

(45x) + ∠TRS = 180     Subtract 45x on both sides

∠TRS = 180 - 45x  


A triangle is also 180°, so the three angles add up to 180°.

∠R + ∠T + ∠S = 180°    [∠R is also ∠TRS]

(180 - 45x) + (25x) + (57 + x) = 180

180 - 45x + 25x + 57 + x = 180     Combine like terms

237 - 19x = 180       Subtract 237 on both sides

-19x = -57      Divide -19 on both sides

x = 3

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Each spin consists in a choice of a number among 1, 3, 4 and 6. This means that there are two odd numbers and two even numbers.

You get an even number if you sum two numbers with the same parity, you get an odd number if you sum two numbers with opposite parity.

Whatever number you get from the first spin, you have a 50% chance of spinning a number with the same parity with the second spin, and a 50% chance of spinning a number with opposite parity with the second spin.

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3 years ago
Use the equation c = k + 2 to find the value of c when k = 8.
11111nata11111 [884]

Answer:

10

Step-by-step explanation:

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6 0
3 years ago
Solve the system of equations
Aneli [31]

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(4 pts) If a rock is thrown vertically upward from the surface of Mars with an initial velocity of 15m/sec
Yuliya22 [10]

Answer:

Step-by-step explanation:

I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.

The position equation is

s(t)=-1.86t^2+15t  That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.

The first derivative of position is velocity:

v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):

0 = -3.72t + 15 and solve for t:\

-15 = -3.72t so

t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:

s(4.03) = -1.86(4.03)² + 15(4.03) so

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7 0
3 years ago
Can someone show me the steps to solve this
saul85 [17]

Answer:

87 - 18 \sqrt{6}

Step-by-step explanation:

We want to expand:

( \sqrt{6} - 9)^{2}

We expand to get:

( \sqrt{6}  - 9)( \sqrt{6}  - 9)

\sqrt{6} ( \sqrt{6}  - 9) - 9( \sqrt{6}  - 9)

We expand using the distributive property to get:

6 - 9 \sqrt{6}  - 9 \sqrt{6}  + 81

6 - 18 \sqrt{6}  + 81

Finally simplify to get:

87- 18 \sqrt{6}

6 0
4 years ago
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