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Svetllana [295]
4 years ago
6

Please help!!!! I just need help with part c.

Mathematics
1 answer:
umka21 [38]4 years ago
6 0

A) the growth is 56% per week. The 1.56 is multiplying the weight of the pumpkin now by the 56% to get the total weight after the 56% increase.


B) Replace P with 80 and solve for n:

80 = 25(1.56)^n

Divide each side by 25:

80/25 = 1.56^n / 25

3.2 = 1.56^n

Take the natural logarithm of both sides:

ln(3.2) = ln(1.56^n)

Remove the exponent:

ln(3.2) = n(ln(1.56)

Divide both sides by ln(1.56)

n = ln(3.2) / ln(1.56)

n = 2.6 weeks, round to 3 weeks.


C)  Change 1.56 to 1.32 and redo the same calculation from B.

80 = 25(1.32)^n

80/25 = 1.32^n /25

3.2 = 1.32^n

ln(3.2) = ln(1.32^n)

ln(3.2) = n(ln(1.32)

n = ln(3.2) / ln(132)

n = 4.2, round to 4 weeks.





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C

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bezimeni [28]
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3 years ago
Find area of the shaded region.
Monica [59]

Answer:

The area of the shaded region is about 38.1 square centimeters.

Step-by-step explanation:

We want to find the area of the shaded region.

To do so, we can first find the area of the sector and then subtract the area of the triangle from the sector.

The given circle has a radius of 6 cm.

And the given sector has a central angle of 150°.

The area for a sector is given by the formula:

\displaystyle A=\pi r^2\cdot \frac{\theta}{360^\circ}

In this case, r = 6 and θ = 150°. Hence, the area of the sector is:

\displaystyle \begin{aligned}A&=\pi(6)^2\cdot \frac{150}{360}\\ &=36\pi\cdot \frac{5}{12}\\&=3\pi \cdot 5\\&=15\pi \text{ cm}^2\end{aligned}

Now, we can find the area of the triangle. We can use an alternative formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle between them.

Both side lengths of the triangle are the radii of the circle. So, both side lengths are 6.

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\displaystyle A=\frac{1}{2}(6)(6)\sin(150)=18\sin(150)

The area of the shaded region is equivalent to the sector minus the triangle:

A_{\text{shaded}}=A_{\text{sector}}-A_{\text{triangle}}

Therefore:

A_{\text{shaded}}=15\pi -18\sin(150)

Use a calculator:

A_{\text{shaded}}=38.1238...\approx 38.1\text{ cm}^2

The area of the shaded region is about 38.1 square centimeters.

6 0
3 years ago
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Mashutka [201]

Answer:

Step-by-step explanation:

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