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Musya8 [376]
3 years ago
9

PLEASE PLEASE HELPPP PLEASEEEEEEEEEEEEEEE

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Here you go pall, have a nice day

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The expression 2.85+2.70M gives the taxi fare in dollars for a trip of M miles. On Thursday you got a find Miss Hearst took a ta
horrorfan [7]

<u><em>Answer:</em></u>

Total fair of the two trips was $32.7

<u><em>Explanation:</em></u>

<u>We are given that the expression that taxi fair is:</u>

2.85 + 2.7M where M represents the number of miles

<u>1- For Thursday:</u>

Number of miles covered = M = 6 miles

<u>Substitute with M=6 in the given equation to get the fair on Thursday as follows:</u>

Fair on Thursday = 2.85 + 2.7(6) = $19.05

<u>2- For Friday:</u>

Number of miles covered = M = 4 miles

<u>Substitute with M=4 in the given equation to get the fair on Friday as follows:</u>

Fair on Friday = 2.85 + 2.7(4) = $13.65

<u>3- The total fair:</u>

Total fair = fair on Thursday + fair on Friday

Total fair = 19.05 + 13.65 = $32.7

Hope this helps :)

4 0
3 years ago
Solve the formula for x.<br> V=2πrx+6πr2
Anna [14]

Answer:

x=−18.849556r2+v/6.283185r

Step-by-step explanation:

Step 1: Flip the equation.

18.849556r2+6.283185rx=v

Step 2: Add -18.849556r^2 to both sides.

18.849556r2+6.283185rx+−18.849556r2=v+−18.849556r2

0r 2+6.283185rx=−18.849556r2+v

Step 3: Divide both sides by 6.283185r. 0r2+6.283185rx/

6.283185r = −18.849556r2+v/6.283185r

x=−18.849556r2+v/6.283185r

7 0
3 years ago
Read 2 more answers
Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h
Anton [14]

Answer:

\frac{4}{3}

Step-by-step explanation:

The area of a regular octahedron is given by:

area = 2\sqrt{3}\ *edge^2. Let a is the length of the edge (diagonal).

area = 2\sqrt{3}\ *a^2

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a

The area of a tetrahedron is given by:

area = \sqrt{3}\ *edge^2 = \sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3}    *a^2

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = \frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}

7 0
4 years ago
Now who keeps sending links lol
Romashka [77]
I don’t know but it is really annoying and they need to stop. they are virus’
7 0
3 years ago
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The____of an angle is the ratio of the opposite leg length to the adjacent leg length.
Helen [10]
Tangent, the acronym SOH-CAH-TOA can help, SOH= sine over hypotenuse, CAH= cosine over hypotenuse, and TOA= opposite over adjacent

4 0
3 years ago
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