All categories

2 years ago

Two positive integers are 3 units apart on a number line. Their product is 108.

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

7 0

Answer:

d) the numbers are 9 and 12

Step-by-step explanation:

set each factor equal to 108:

m-12=108

m = 120

*************

m-9=108

m=117

*************

120 and 117 are 3 units apart

****************

9 x 12 = 108

You might be interested in

If David plays 3 tennis matches every week for 9 weeks, how many matches will he play altogether

kari74 [83]

If he plays 3 matches a week for 9 weeks, you have to multiply 3&9.
3*9=27
Daniel will have played 27 tennis matches by the end of the 9 weeks.
Hope this helps:)

5 0

3 years ago

Read 2 more answers

!NUMBER 4! please help!! show all work please

snow_lady [41]

Answer:

C. 88

Explanation:

f(x) = 4x + 8 || g(x) = x² + x

fg( -5 )

go from right to left in such function problems.

replace x with [ -5 ]

f( (-5)² -5)

f(20)

[ replace x with 20 ]

4(20) + 8

80 + 8

7 0

2 years ago

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.