Find the volume of a rectangular box having width 4.2 ft, length 8.694 ft, and height 7.643 ft.

Ive been on this test for a long time pleaseeee

Setler79 [48]

f(x) = 200x - 7

Hope this helps! ;)

5 0

3 years ago

4)

erastovalidia [21]

Answer:

D.) 4x + y

Step-by-step explanation:

3x + x + y

Add 3 x and x .

4 x + y

7 0

3 years ago

Rectangle ABCD has vertices A(3, 5), B(5,5), C(5, 1) and D(3, 1). Drag and drop the coordinates of each vertex when rectangle AB

garik1379 [7]

Answer:

Given the coordinates of rectangle ABCD are;

A = (3, 5)

B = (5,5)

C = (5, 1) and

D = (3, 1)

The rule of rotation 90 degree counter-clockwise around the origin is given by;

$(x, y) \rightarrow (-y, x)$

Now, the coordinates of each vertex when rectangle ABCD is rotated 90 degree counter-clockwise around the origin are;

$A(3, 5) \rightarrow A'(-5, 3)$

$B(5, 5) \rightarrow B'(-5, 5)$

$C(5, 1) \rightarrow C'(-1, 5)$

$D(3, 1) \rightarrow D'(-1, 3)$

5 0

3 years ago

You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inch

Schach [20]

Answer:

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

Step-by-step explanation:

Given;

Length of the room = 12 feet 6 inches = 12.5 ft

Breadth of the room = 10 feet 6 inches= 10.5ft

Height of the room = 8 feet

Window = 4 ft by 3ft

door = 7ft by 3 ft

Wall paper = 30 inches by 30ft = 2.5ft by 30ft

The total area of the walls of the room is;

Area = Area of the four walls - Area of the two windows and a door.

A = 2LH + 2BH - Area of windows and door

A = 2(12.5×8) + 2(10.5×8) - 2(4×3) -(7×3)

A = 323ft^2

Allowing 10% waste, total area of wallpaper needed is;

At = 323 × 1.10 = 355.3ft^2

Area of wallpaper Aw= 2.5×30 = 75ft^2

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

3 0

3 years ago

Consider the two vectors m~ = (a,

Aloiza [94]

Answer:

0

Step-by-step explanation:

We are given the following vectors:

m = (a, b) = ai + bj

n = (c, d) = ci + dj

Values of a,b,c and d are given to be: a = 4, b = 4, c = 2, and d = −2

So, the vectors we have will be:

m = (4, 4) = 4i + 4j

n = (2, -2) = 2i - 2j

We need to find the magnitude of vector product m x m.

Remember that the vector(cross) product of a vector with itself is always 0. For any two vectors A and B, the magnitude of their vector(cross) product is defined as:

A x B = AB sin(θ)

Here, θ is the angle between two vectors A and B. if A and B represent the same vector then the angle θ will be zero. Since sin(θ) = 0, the magintude of the vector product will also be 0.

Therefore, for our question, the magnitude of the vector product m x m will be equal to 0.

7 0

3 years ago