Answer:
12-14 october
Explanation:
The probable period of exposure is calculated as follows:
- Know the range of the incubation period
- Start counting back from the days of the first case by subtracting the first number of incubation period range
- Count back the days from the last case by subtracting the last number of incubation period range.
- This will give a range which will be the period of exposure.
From the question,
- Incubation period range 1-15
- Date of first case = october 15
- Therefore, first date of exposure = 15 -1 = 14
- Date of last case = 22
- Therefore, last date of exposure = 27 - 15 = 12
- Thus, the range is 12-14 october which is the probable period of exposure.
Glucose particles are ingested from gastrointestinal cells into the circulatory system. The circulation system then, at that point, conveys the glucose particles all through the body. Glucose enters every cell of the body and is involved by the cells mitochondrion as fuel.
Answer:
The organism's parents have to either be heterogeneous dominant or homogeneous.
Explanation:
When the traits get passed down they either have to have 2 dominant traits or a mix.
Nothing
Explanation:
Mass of the sample = 500g
Decay rate per anum = 11%
Unknown:
Mass of sample remaining after 10yrs = ?
Solution:
This is a simple percentages problem;
The radioactive sample loses 
x 500g of sample per year;
this is a loss of 55g per year;
In 10years time, the sample would have lost 10 x 55g = 550g of element.
Since our sample is not up to 550g, then no amount of sample will remain after 10yrs.
learn more:
Radioactive decay brainly.com/question/10094982
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<span>When an athlete is nearing the end of a race and her cells are low on oxygen, it is likely to be fermentation. When cells have used up all their oxygen they ferment glucose into lactic acid. Fermentation is a metabolic process that consumes sugar in the absence of oxygen</span>
