Answer:
.
Step-by-step explanation:
Two numbers that add up to -19 and multiply to 48 are -16 and -3:
![(x^4-19x^2+48)=0\\(x^2-16)(x^2-3)=0\\(x+4)(x-4)(x^2-3)=0](https://tex.z-dn.net/?f=%28x%5E4-19x%5E2%2B48%29%3D0%5C%5C%28x%5E2-16%29%28x%5E2-3%29%3D0%5C%5C%28x%2B4%29%28x-4%29%28x%5E2-3%29%3D0)
So, the solutions come from each parentheses: x+4=0, x-4=0, and x^2-3=0.
x+4=0
x = -4
x-4=0
x = 4
x^2-3=0
x^2 = 3
x = +/- √3
So, the solutions are -4, -√3, √3, and 4.
Answer:
x=5
y=4
Step-by-step explanation:
Step 1:
Let us solve for <em>x</em> using the
equation by <u>isolating terms containing the variable</u>:
![4x-7=13\\4x=20\\\fbox{x=5}](https://tex.z-dn.net/?f=4x-7%3D13%5C%5C4x%3D20%5C%5C%5Cfbox%7Bx%3D5%7D)
Great! <em>x</em> is 5... let's find <em>y</em>.
Step 2:
Since we know the value of <em>x</em>, we can use what we know to find <em>y</em> using the <u>other equation</u>:
![5x-2y=17\\](https://tex.z-dn.net/?f=5x-2y%3D17%5C%5C)
<em>Given that x=5, we can </em><u><em>replace</em></u><em> x with 5</em>.
![5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}](https://tex.z-dn.net/?f=5%2A5-2y%3D17%5C%5C25-2y%3D17%5C%5C2y%3D8%5C%5C%5C%5C%5Cfbox%7By%3D4%7D)
<em>I hope this helps! Let me know if you have any questions :)</em>
Answer:
x = 6
Step-by-step explanation:
move all terms to the left:
-1.5x+12-(2.5x-12)=0
get rid of parentheses
-1.5x-2.5x+12+12=0
add all the numbers together, and all the variable.
-4x+24=0
move all terms containing x to the left, all other terms to the right
-4x=-24
x=-24/-4 - divide
x=+6