Alonzo, Alice, and Juan all solved the following problem but got different answers:

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

5 0

Answer:

Juan believes the answer is -2/15.

Step-by-step explanation:

The given problem is :

$\dfrac{-1}{3}\times \dfrac{2}{5}$

We need to solve the problem.

$\dfrac{-1}{3}\times \dfrac{2}{5}=\dfrac{-1\times 2}{3\times 5}\\\\=\dfrac{-2}{15}$

So, the answer to the problem is $\dfrac{-2}{15}$ . Hence, Juan is correct.

You might be interested in

Find the value of a.<br> 4x + ax = - 2x(2x + 1)

Karo-lina-s [1.5K]

Answer:

a = -2(2x+1)-4

Step-by-step explanation:

1. Factor out the common term x.

x(4+a)= -2x(2x+1)

2. Cancel x on both sides.

4+a= -2(2x+1)

3. Subtract 4 from both sides.

a= -2(2x+1)-4

3 0

2 years ago

PLEASE HELP

kogti [31]

$\textbf{You have to}$ restrict the domains of quadratic functions and absolute value functions, because these functions are $\textbf{many-to-one}$ functions. For instance, the quadratic function f(x) = x^2 pairs both −2 and 2 with 4, and the absolute value function f(x) = |x| pairs both −2 and 2 with 2.

Linear functions (excluding constant functions) and exponential functions are $\textbf{one-to-one}$ functions, so their domains $\textbf{do not need}$ to be restricted.
_________________

An absolute value function, without domain restriction, has an inverse that is NOT a function.

In order to guarantee that the inverse must also be a function, we need to restrict the domain of the absolute value function to make it a one-to-one function.

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME.............

Brums [2.3K]

Answer:

$g(x)=3x^2$