Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
#1
Area of base=1/2(2.8)(4.2)
Volume:
- Area of base×Height
- 5.88(7)
- 41.16in³
#2
Area of base
- 6×1/2(7)(6.1)
- 3(7)(6.1)
- 128.1cm²
Volume:-
Answer:
Step-by-step explanation:
16 ticks, the pointer is on 12. there fore it is the second answer.
2 3/4 lb
The first answer of part A is 32
So 4y means you have to multiply 4 by y, which is 20 since 4x5=20
And then you add 12, which is 32.
The second answer to part A is 40
With the second question of part a, the expression is basically saying 4 times whatever 5+3 is. So 5+3= 8, and 4(8) is 40
For part B, they are equivalent because let’s pretend y=2. 12+4y= 20. And then 4(y+3) would equal 20 because 4(2)=8 and 4(3)=12 and 8+12=20. This might not be the answer that your teacher is looking for, but it’s still a right answer so technically they can’t say it’s wrong unless you have a super unfair teacher
Answer:
Step-by-step explanation:
Given the equation 
Step 1;
Expand the bracket at the right hand side of the equation to have:
Taking the reciprocal of both sides:
