<span>A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
A. 2.25 s; 5 ft
B. 1.13 s; 25.25 ft
C. 1.13 s; 27.5 ft
D. 1.13 s; 65.75 ft <====
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6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
Whoever sees this have a great day ❤️
Answer:
2/16
Step-by-step explanation:
i just doubled he equation
Answer:
slope: 3
equation of the line: y=3x+4
Step-by-step explanation:
i hope this helps :)