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4 years ago

Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.

Mathematics

1 answer:

Andreas93 [3]4 years ago

6 0

Answer: k = {8, -8}

Step-by-step explanation:

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero. → b² - 4ac = 0

4x² + kx + 4 = 0

↓ ↓ ↓

a=4 b=k c=4

b² - 4ac = 0

k² - 4(4)(4) = 0

k² = 64

k = √64

k = ± 8

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Simora [160]

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3(8 - 2) + 4 = 22

Parentheses...

3(8 - 2) + 4 = 22

8 - 2 <<<In the parentheses so you must solve first

so...

3(6) + 4 = 22

Multiplication...

3(6) + 4 = 22

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so..

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Addition...

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18 + 4

so...

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3 years ago

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