Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.
1 answer:
Answer: k = {8, -8}
<u>Step-by-step explanation:</u>
In order for a quadratic equation to have exactly one solution, the discriminant must equal zero. → b² - 4ac = 0
4x² + kx + 4 = 0
↓ ↓ ↓
a=4 b=k c=4
b² - 4ac = 0
k² - 4(4)(4) = 0
k² = 64
k = √64
k = ± 8
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Answer:
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