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notsponge [240]
3 years ago
14

GIVING BRAINLIEST NO LINKS

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0
The answer is A most definitely
Murljashka [212]3 years ago
4 0

Answer: 46

Step-by-step explanation:

All you have to do is see the different possibilities that can happen

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Help me please find x for this triangle!!!!
Ne4ueva [31]

Answer:

x=30

Step-by-step explanation:

Since the measure of an exterior angle is equal to the sum of any two angles in a triangle, the equation would be 4x-18=2x+6+36. Solve this, and we get x=30.

Hope this helped!

5 0
3 years ago
Solve the equation:<br><br> 2m + 45 = 49
Amiraneli [1.4K]

Answer:

m=2

Step-by-step explanation:

2m=4

m=2

if my answer helps please mark as brainliest.

3 0
3 years ago
Read 2 more answers
An experiment consists of tossing a die and then flipping a coin once if the number on the die is even. If the number on the die
Mice21 [21]

Answer:

\Omega = \{ 1HH, 1HT, 1TH, 1TT, 2H, 2T, 3HH, 3HT, 3TH, 3TT, 4H, 4T,\\5HH , 5HT, 5TH, 5TT, 6H, 6T \}

The probability is 3/12. The third option is correct.

Step-by-step explanation:

The sample space is

\Omega = \{ 1HH, 1HT, 1TH, 1TT, 2H, 2T, 3HH, 3HT, 3TH, 3TT, 4H, 4T,\\5HH , 5HT, 5TH, 5TT, 6H, 6T \}

Note that this sample space is not equally probable.

The probability of getting a given number followed is the probability of getting an even number from the 6 numbers (3/6) multiplied by the probability of getting a head after getting that even number, that is 1/2, because is equally probable to get heads or tails from one single coin toss (note that we are assuming that the dice was even, thats why there is a single coin toss).

Therefore, the probability of getting an even number and a head is

P( D in {2,4,6} , H = 1) = P(D in {2,4,6}) * P(H=1 | D in {2,4,6}) = 3/6 * 1/2 = 3/12.

5 0
3 years ago
How can i solve this problem <br> 6x+5y=13<br> 5x+4y=10
natka813 [3]
System of equations

11x+9y=23
Solve the rest I gave you the baseline hope it helps!
4 0
3 years ago
A population of 40,000 decreases by 3.1% each year. what is the approximate population in 4 years
coldgirl [10]

\bf \textit{Amount of Population Decay} \\\\ A=Pe^{-rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &40000\\ r=rate\to 3.1\%\to \frac{3.1}{100}\dotfill &0.031\\ t=\textit{elapsed time}\dotfill &4\\ \end{cases} \\\\\\ A=4000e^{-0.031(4)}\implies A=40000e^{-0.124}\implies A=\cfrac{4000}{e^{0.124}} \\\\\\ A\approx 35335.194\implies \stackrel{\textit{rounded up}}{A\approx 35335}

7 0
3 years ago
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