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3 years ago

What is the remainder when when f(x)=x3+3x2−10x−14 is divided by (x-4) ?

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

With Horner's Method.

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A 16 oz bottle of water costs $1.44. What is the cost per ounce?

oksano4ka [1.4K]

the bottle of waters costs 0.09 cents per ounce.

5 0

4 years ago

Read 2 more answers

Solve the equation x^2=26

Volgvan

Take the square root. The opposite of squaring something is taking the root :)

√x^2 = √26

x = √26

x = 5.099...

OR leave it if your teacher doesn't want a decimal since it can't be simplified anymore

8 0

3 years ago

Find the inverse of the function.

asambeis [7]

Answer:

A) $f^{-1}(n)= (n+2)^3$

Step-by-step explanation:

$f(n) = \sqrt[3]{n} -2$

$y = \sqrt[3]{n} -2$

$y = n^{1/3}-2$

$n = y^{1/3} -2$

$n + 2 = y^{1/3}$

$y = (n + 2) ^3$

$f^{-1}(n) = (n + 2)^3$

Hope this helps!

7 0

3 years ago

Read 2 more answers

Find the geometric mean for the following numbers 32 and 2

MaRussiya [10]

First take the product 2 times 32 is 64 because there are only two numbers the nth root is the square root, and the square root of 64 is 8. Therefore geometric mean of 2 and 32 is 8

8 0

4 years ago

Surface-finish defects in a small electric appliance occur at random with a mean rate of 0.3 defects per unit. find the probabil

mario62 [17]

Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

Step-by-step explanation:

Since we have given that

Mean rate defects per unit = 0.3

Since we will use "Poisson distribution":

$P(X=K)=\frac{e^{-\lambda}\lambda^k}{k!}$

But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.

$P(X\geq 2)=1+P(X=0)+P(X=1)$

So,

$P(X=0)=\frac{e^{-0.3}0.3^0}{0!}=e^{-0.3}=0.74\\\\P(X=1)=\frac{e^{-0.3}\times 0.3}{1}=0.22$

so, it becomes,

$P(X>2)=1-(0.74+0.22)=1-0.96=0.04$

Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

4 0

4 years ago