Answer:
I cant see the pic whats the pro
blem
Step-by-step explanation:
Answer: $840
Step-by-step explanation:
- Set up the proportion 210/10 = x/40.
- To solve it quickly, multiply 210 with 4, since 10*4 = 40. Therefore, x = 840.
Answer:
By 71 years of age 80% of the plan participants have passed away.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 68 years and a standard deviation of 4 years.
This means that ![\mu = 68, \sigma = 4](https://tex.z-dn.net/?f=%5Cmu%20%3D%2068%2C%20%5Csigma%20%3D%204)
By what age have 80% of the plan participants passed away?
By the 80th percentile of ages, which is X when Z has a p-value of 0.8, so X when Z = 0.84.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![0.84 = \frac{X - 68}{4}](https://tex.z-dn.net/?f=0.84%20%3D%20%5Cfrac%7BX%20-%2068%7D%7B4%7D)
![X - 68 = 4*0.84](https://tex.z-dn.net/?f=X%20-%2068%20%3D%204%2A0.84)
![X = 71](https://tex.z-dn.net/?f=X%20%3D%2071)
By 71 years of age 80% of the plan participants have passed away.
Using function concepts, it is found that the correct statement is given by:
all of the x-intercepts of f(x) are common to those of g(x).
<h3>What are the x-intercepts of the functions?</h3>
They are the values of x when x = 0, hence:
- For g(x), it is of x = -1 and x = 1.
- For f(x), it is of x = -1.
Hence, the first statement is correct, and the x-intercept x = -1 of f(x) is common to the x-intercept x = -1 of g(x).
More can be learned about function concepts at brainly.com/question/25537936
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