1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natali 33 [55]
3 years ago
15

In a geometric sequence, the first term is 3 and the common ratio is 2. What is the sum of the first 9 terms?

Mathematics
1 answer:
Solnce55 [7]3 years ago
7 0

Step-by-step explanation:

99 is the answer........

You might be interested in
Please help i need answers am bad at math
den301095 [7]

Answer:

1) 2 5/9

2) 4 5/6

3) 4 3/8

4) 5 3/5

5) 7 1/3

6) 6 1/9

7) 7 1/8

8) 2 2/9

9) 5 3/4

Step-by-step explanation:

Hope this helps

5 0
3 years ago
Sarah spends a total of $60. Based on the information in the table, how many people attended the craft demonstration?
____ [38]
Divide 60 by however much people was there to get your answer


Hope it works
7 0
3 years ago
Read 2 more answers
This is the difference between the estimated value and the true value<br> hint: first letters co
Gemiola [76]

Answer:

correction

Step-by-step explanation:

6 0
4 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
Please help! Thanks!
Ede4ka [16]
-9(6m-3)+6(1+4m)
=54m+27+6(1+4m)
=54m+27+6+24m
= -30m+33

5 0
3 years ago
Other questions:
  • Can someone please help with this 7th grade math question?
    9·1 answer
  • Wren and Jenni are reading the same book. Wren is on page 12 and reads 4 pages every night. Jenni is on page 4 and reads 5 pages
    8·1 answer
  • What is the value of X (x+40) (3x)
    14·1 answer
  • Problem Solving
    6·1 answer
  • Plz help me I need the answer ASAP please
    12·2 answers
  • I don’t understand this can someone please help me thank you :)
    5·2 answers
  • 1. Sarah went to dinner, and the bill was $15.25. She left a 15% tip. How
    5·2 answers
  • The National Center for Education Statistics would like to test the hypothesis that the proportion of Bachelor's degrees that we
    14·1 answer
  • According to the video, what are some risks faced by Registered Nurses? Check all that apply.
    15·1 answer
  • Please help asap tysm &lt;3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!