Answer:
x = 6 ; y = -9
Step-by-step explanation:
8 x + 2 y = 30 ..........equ No 1
7 x + 2 y = 24......... equ No 2
8 x = 30 - 2y
∴ x =
substituting the value of x in equ No 2
7 
+ 2 y = 24
7 ( 30 -2 y) + 2 y × 8 = 24 × 8
7 × 30 - 14 y + 16 y = 192
210 + 2 y = 192
2 y = 192 - 210
2 y = - 18
∴ y = - 9
put y = -9 , 8 x = 30 - 2 y
8 x = 30 - 2 ( -9)
8 x = 30 - ( -18)
8 x = 48
∴ x = 6
x = 6 ; y = -9
The answer is d= -2an+2s/n^2-n
That answer should be in a fraction form.
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer:
d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))
Step-by-step explanation:
The Law of Sines tells us that sides of a triangle are proportional to the sine of the opposite angle. This can be used along with a trig identity to demonstrate the required relation.
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<h3>top triangle</h3>
The law of sines applied to the top triangle is ...
BC/sin(A) = AC/sin(θ)
Triangle ABC is isosceles, so the base angles at B and C are congruent. Then the angle at vertex A is ...
∠A = 180° -θ -θ = 180° -2θ
A trig identity tells us the sine of an angle is equal to the sine of its supplement. That means the sine of angle A is ...
sin(A) = sin(180° -2θ) = sin(2θ)
and our above Law of Sines equation tells us ...
BC = sin(A)/sin(θ)·AC = k·sin(2θ)/sin(θ)
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<h3>bottom triangle</h3>
The law of sines applied to the bottom triangle is ...
DC/sin(B) = BC/sin(D)
d/sin(α) = BC/sin(β)
Multiplying by sin(α) we have ...
d = BC·sin(α)/sin(β)
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Using our expression for BC gives the desired relation:
d = k·sin(2θ)·sin(α)/(sin(θ)·sin(β))
