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Alina [70]
3 years ago
6

The picture is above I’ll mark as brainliest.

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

A. 42 u^{2}

Step-by-step explanation:

The area of the figure is length × width. The length of the figure is 7 units, and the width is 6 units.

Finding the area:

length × width

= 7 × 6

= 42 u^{2}

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Solve the equation 2p/3-12=-2
-BARSIC- [3]
Hey there! 

\frac{2p}{3} - 12 = -2

Firstly, we are going add 12 on each of the sides that we're working with. like ↓ 

p - 12 + 12 \\ \\ = -2 + 12

This gives us \frac{2}{3}p = 10 (if you are wondering how we got the out come of 10 it is because I added -2 + 12 = 10

Now multiply \frac{3}{2} on each of your sides 

\frac{3}{2} ( \frac{2}{3}p)  \\ \\  =  \frac{3}{2} (10)

Cancel the first set and you will find the value of p

p = 15

Good luck on your assignment and enjoy your day 

~LoveYourselfFirst:)
5 0
3 years ago
The perimeter of an equilateral triangle is 51 feet.what is the length of one of its side?explain your work
satela [25.4K]

Hello!

The answer is: 17 ft.

Explanation:

To find this out, just divide the perimeter, and the amount of sides in a triangle, which is 3. This will only work with equilateral triangles because an equilateral triangle has all three sides the same length. Anyway, divide 51 and 3. (51 / 3 = 17) Just to make sure, you can add three 17's together, 17 + 17 + 17 = 51, the perimeter.

I hope this helped! ~Q

4 0
3 years ago
Read 2 more answers
Which is a solution to (x − 2)(x + 10) = 13?
Romashka-Z-Leto [24]
You'll need to expand <span>(x − 2)(x + 10) first,

</span><span>(x − 2)(x + 10) = 13
</span>x^2+8 x-20=13
x^2+8 x+16=49
(x+4)^2=49
x+4= \pm 7
x=3 , x=-11
3 0
3 years ago
Anthony makes candies. FIrst, he mixes 1 cup of cream with 2 cups of chocolate. In all, he uses 9 cups of these two ingredients
lisabon 2012 [21]

Answer:

3 cups of cream

2 cups of chocolate

Step-by-step explanation:

9/3 = 3

1 x 3 = 3

2 x 3 = 6

6+3 = 9

5 0
3 years ago
Read 2 more answers
On a graph with y-values ranging from 1,013,020 to 9,618,115, what is a reasonable scale to use on a y-axis with 10 tick marks?
Travka [436]
Divide the range range between 10 fo find the appropriate scale.

[9618115 - 1013020]/10 = 8605095/10 = 860509.5

Then use scale 1: 1000000. So your marks will be

1 = 1000000
2 = 2000000
3 = 3000000

... 10 = 10000000
8 0
3 years ago
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