A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Answer:
c3po 1049596979ebsbsnwnanxbxjxo o ocjsbzbxbbxh h h.
9 inches
Step By Step
3 1\10
Answer:
$1654
Step-by-step explanation:
332+230= 562
273*4+562
1092+562
1654
