How many pieces of gum are in 4 packages of gum?

10(g+5)=2(g+9). please help

MAVERICK [17]

Answer:

g=-4

Step-by-step explanation:

7 0

3 years ago

Use the function below to find F(4). F(x)= 1/3•4x

Leni [432]

F(4) = 1/3 x 4(4)
=1/3 x 16
= 16/3

8 0

3 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

3 years ago

Read 2 more answers

Through which pairs of points is the slope negative? Select all that apply. a. (3, 6) and (10, 6)

xeze [42]

Trial and error on this one try each pair till you find negative slopes
C and D

5 0

3 years ago

You meet with the financial aid office to discuss your costs for attending MGA next semester. Tuition is $113.67 per credit hour

jenyasd209 [6]

Answer:

$1615.05

Step-by-step explanation:

First the cost. We know that tuition per credit hour is 113.67 and there is a flat fee of 660. This can be represented by 113.67h + 660, where h is equal to the number of credit hours.

Next, the amount paid. There are two constants of 350 and 400 already there. We can represent the remaining amount that needs to be paid by another variable, x.

Now, the cost needs to be equal to the amount you pay. We can replace h with 15 for 15 hours and solve for x.

113.67h + 660 = 350 + 400 + x

113.67(15) + 660 = 350 + 400 + x

1705.05 + 660 = 750 + x

2365.05 = 750 + x

1615.05 = x

3 0

3 years ago