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3 years ago

In triangle ABC, m<A = 8x +12, m<B = 5x+14, m<C = 2x +4. What is the m<A ? Need help....please

1 answer:

6 0

Triangle
m<A + m2x +4 = 180
15x + 30 = 180
15x = 180 -30
15x = 150
x = 10

m<A = 8x +12
m<A = 8(10) +12
m<A = 80 + 12
m<A = 92

answer
m<A = 92

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Hey want help me??!! ill mark you as brainn!!pleasee!

Andru [333]

Answer:

Here, length is 8 in. Width is 4in. and height is (3+3+3)=9 in. Then use the formula.

A= 2wl+2hl+2hw

= 2×4×8 + 2×9×8+2×9×4

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3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago

Please help me! I will mark brainliest. Also, the perimeter is 36 feet.

Lynna [10]

9 feet? Not sure lmk if I'm wrong other people answering

8 0

3 years ago

Read 2 more answers

The area of a rectangle whose perimeter is a fixed 80 feet is given by A=40w - w2 , where w is the width of the rectangle. Deter

Stolb23 [73]

Answer:

Width=20 feet

Since Length=Width=20 feet, the rectangle is a Square.

Step-by-step explanation:

Area, $A=40w - w^2$

To determine the width of the rectangle that gives the maximum area, we take the derivative of A and solve for its critical point.

$A'=40 - 2w\\$When A'=0\\40-2w=0\\40=2w\\w=20 feet$

The width of the rectangle that gives the maximum area =20 feet.

Perimeter of a rectangle=2(l+w)

Perimeter of the rectangle=80 feet

2(l+w)=80

2l+2(20)=80

2l=80-40

2l=40

l=20 feet

Since the length and width are equal, the special type of rectangle that produces this maximum area is a Square.

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3 years ago

Question 4 of 25

Gnoma [55]

Answer:

Step-by-step explanation:

We are looking for P(58 < x < 64). We need to find the percentage to the left of the z-scores for each of these numbers. To find the z scores, use the formula:

$z=\frac{x_i-\bar{x}}{\sigma}$

$z=\frac{58-62}{4}$ which gives us a z-score of -1. The percentage of numbers to the left of a z-score of -1 is .1586553

Now for the other z-score:

$z=\frac{64-64}{4}$ which gives us a z-score of .5. The percentage of numbers to the left of a z-score of .5 is .69146246

The lower percentage subtracted from the higher gives the area in question:

.69146246 - .1586553 = .53280716, or as a percentage, 53.3%, choice A.

7 0

3 years ago