IM bad at algebra so please helpppp......

Mathematics

1 answer:

hram777 [196]2 years ago

5 0

Answer:

Company A:

Mean: 44.1

Median: 43

IQR: 18.5

Standard Deviation: 9.8

Company B:

Mean: 49.1

Median: 51

IQR: 20.5

Standard Deviation: 12

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Maria took a math test last week. The table shows how many questions she answered correctly and incorrectly.

pashok25 [27]

Answer:

Step-by-step explanation:

Maria had a test with 20 questions

if 17 are correct,

20 questions................................100%

17 questions................................?%

she was 85% right

5 0

3 years ago

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$