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Sidana [21]
2 years ago
6

IM bad at algebra so please helpppp......

Mathematics
1 answer:
hram777 [196]2 years ago
5 0

Answer:

Company A:

Mean: 44.1

Median: 43

IQR: 18.5

Standard Deviation: 9.8

Company B:

Mean: 49.1

Median: 51

IQR: 20.5

Standard Deviation: 12

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The standard deviation of number of hours worked per week for these workers is 3.91.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

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In this problem we have that:

The average number of hours worked per week is 43.4, so \mu = 43.4.

Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.

This means that the Z score of X = 48 has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use Z = 1.175.

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