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Zarrin [17]
3 years ago
13

Ill brainlist you plus give you more points if needed I have atleast 40 somthing after this

Mathematics
2 answers:
Furkat [3]3 years ago
8 0

Answer: B

Step-by-step explanation:

Naya [18.7K]3 years ago
3 0

Answer:

I think its 1/6

Step-by-step explanation:

cause there are six numbers so the probility is out of six

that could be wrong not 100% sure its been a while  

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In a large population, 57 % of the people have been vaccinated. If 5 people are randomly selected, what is the probability that
My name is Ann [436]

Answer:

0.986

Step-by-step explanation:

Probability of at least one being vac = 1 - Probability of all 5 not vac

1 - (1-0.57)^5 = 1 - (0.43^5) = 1 - 0.014 = 0.986

5 0
3 years ago
Find the value of x. Round to the nearest tenth if needed.
Natasha_Volkova [10]
12^2 + 6^2 = x^2
144 + 36 = x^2
180 = x^2
13.416407865 = x

rounded

x = 13.4
8 0
3 years ago
Select the appropriate values of x that are solutions to f (x)=0, where f (x) = -7x^2 +4x+9
Ghella [55]
-7x^2 +4x+9=0\\
\Delta=4^2-4\cdot(-7)\cdot9=16+252=268\\
\sqrt{\Delta}=\sqrt{268}=2\sqrt{67}\\
x_1=\frac{-4-2\sqrt{67}}{2\cdot(-7)}=\frac{-4-2\sqrt{67}}{-14}=\frac{2+\sqrt{67}}{7}\approx1.46\\
x_2=\frac{-4+2\sqrt{67}}{2\cdot(-7)}=\frac{-4+2\sqrt{67}}{-14}=\frac{2-\sqrt{67}}{7}\approx-0.88\\
7 0
4 years ago
Which expression represents the phrase?
34kurt

Sorry I'm late but the answer is D

6 0
3 years ago
Read 2 more answers
Can someone please help me?
Natalka [10]

9514 1404 393

Answer:

  C and D

Step-by-step explanation:

Extraneous solutions arise in a couple of cases, both of which are illustrated in this list of answer choices.

1. Square roots (and other even-index radicals). The square root is defined only for positive arguments. When the radical is removed by squaring the equation, the possibility of negative arguments is introduced. Hence, there may be extraneous solutions.

<u>Example</u>:

  x = √(x +2)   ⇒  x² = x+2 . . . has 2 roots, one of which is extraneous

__

2. Rational function equations. Such an equation is only defined when the denominator is not zero. A method often taught for solution of these equations is "cross-multiplying"--essentially multiplying by the product of the denominators. In the case where this product is not the least common denominator, the equation will have an extra factor that can introduce an extraneous root.

__

The answer choices C and D are likely to have extraneous roots based on the above observations.

_____

<em>Additional comment</em>

Choice D would usually be solved by cross-multiplying. That would give the quadratic equation (x -3)² = 0, which only has solutions x=3. The denominators are zero at x=3, so these solutions are extraneous. If the right side is subtracted from the left side, the fractions can be combined to give ...

  ((x+3) -6)/((x -3)(x +3)) = 0   ⇒   1/(x+3) = 0 . . . . no solution

4 0
3 years ago
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