<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
Answer:
Step-by-step explanation:
One equivalent can be obtain by distributing multiplication with 3 over subtraction 5-2i
3(5-2i) =
3·5 -3·2·i =
15 -6i or -6i +15
Answer:
It can be the line of best fit because it closely fits the data points.
Step-by-step explanation:
The line is near the data points and goes down from left to right just like the data points. It is just above or just below the data points.
