Answer:
the total amount of water supplier per hour to the region within a circle of radius R=110 ( that is from distance r, 0<r<110)
![W(R) = 2\pi [1-(R+1)e^{-R}]](https://tex.z-dn.net/?f=W%28R%29%20%3D%202%5Cpi%20%5B1-%28R%2B1%29e%5E%7B-R%7D%5D)
Step-by-step explanation:
if f(r) describes the water supplied at a distance r , the total amount supplied inside a region that goes from 0 until the circle of radius R, is the sum of all f(r) values from 0 until R, that is the integral value over these limits.
The formula deduction can be found in the attached picture
There is an "r" that multiplies e^-r as result of changing from rectangular coordinates to polar ones.(dx*dy --> r*dr*da)
Answer:
Step-by-step explanation:
To find the center and the radius, we need to put the equation in the (x-a)^2+(y-b)^2=r^2 [a is the x-coordinate, b is the y-coordinate, and r is the radius].
(x+6)^2+(y+7)^2 - 36 - 49 + 69 = 0
(x+6)^2+(y+7)^2 - 16 = 0
(x+6)^2+(y+7)^2 = 16
(x+6)^2+(y+7)^2 = 4^2
The center is (-6,-7) and the radius is 4.
Hope this helps!
Answer:
x + 1/4
Step-by-step explanation: