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3 years ago

2v+46=8(v-1) I got -54/10 which I know is wrong. Please help.

1 answer:

7 0

First, we will get rid of the brackets
2v+46 = 8v-8
then, we will gather the terms with the variables on one side of the equation and the terms with no variables on the other side.
46+8 = 8v-2v
54 = 6v
to get the value of v, we will divide both sides of the equation by 6
v = 54/6 = 9

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Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and x + 7y = 8

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To solve this system by substitution, first isolate x in the second equation.

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Now, plug this expression ( $8-7y$ ) for x in the top equation to solve for y.

$\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}$
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Now that you have y, plug it into the second equation and solve for x.

$x+7y=8$
$x+7(1)=8$
$x+7=8$
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Last step is to plug your x- and y-values in to both equations to check your work.

$\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}$

$\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ; \frac{1}{3} * \frac{8}{8} = \frac{8}{24}$

$\frac{9}{24} + \frac{8}{24} = \frac{17}{24}$ <--True

$1+7(1)=8$
$1+7=8$ <--True

Answer:
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