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lubasha [3.4K]
3 years ago
15

A line is drawn on a coordinate grid by the equation y = 1. Which of the following lines would represent a row perpendicular to

it?
A. a line containing the point (5,2)
B. y = 1
C. x = 4
D. y = 3
Mathematics
1 answer:
DaniilM [7]3 years ago
3 0
The answer is b I think
You might be interested in
Plz help me this is for tomorrow waited last minute
soldi70 [24.7K]
Angle a =40° beacuse they are vertical angle
b will be 180- 40+90=50°
c is making supplementry angle with 65 so c+65=180
c=115°
8 0
4 years ago
How would solve <br>2y+6x=0
Slav-nsk [51]

2y+6x=0

-6x from both sides

2y=-6x+0

then divide by 2 to each side so it looks like this 2y/2=-6x+0/2

the 2 cancels 2y so you're left with y

Then divide -6/2=-3 and 0/2=0

y=-3x+0  

Does that answer your question?

4 0
4 years ago
Please...... !!!!!!!
Artist 52 [7]

Answer:

Answer is 5

Step-by-step explanation:

I did math that's explaining.

4 0
3 years ago
Read 2 more answers
Which is the graph of f(x) = (2/3)^x
Luda [366]

Answer:

Picture attached below.

Step-by-step explanation:

I hope it helps.

6 0
3 years ago
We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th
Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

6 0
4 years ago
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