Answer:
and 
Step-by-step explanation:
Options

Required
Select the unit rates
Unit rate involve two items where the first item being measured can be any positive number, but the second item must be measured in units (i.e. 1)
For clarity:
If
represents unit rate, then 
Having said that:
Only
and
satisfy the condition of unit rates; others are not because they have a denominator other than 1
The sister catches up Jeff after 2 hours
Step-by-step explanation:
We can write Jeff's position and his sister position at time t using the following expressions:
- Jeff position:

where:
7 is the initial position of Jeff when his sister sarts chasing him
2.5 is Jeff's velocity (in miles/hour), so its position increases by 2.5 miles for each hour
t is the time measured in hours
- Sister position:

where
6 is the sister velocity (her position increases by 6 miles for every hour)
t is the time measured in hours
The sister catches up Jeff when the two positions are equal, so

And solving for t,

So, the sister catches Jeff after 2 hours.
Learn more about speed:
brainly.com/question/8893949
#LearnwithBrainly
Answer:
-4
Step-by-step explanation:
<em>Factor by the numbers from left to right.</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>It changes to positive to negative.</em>
<em>-4</em>
<em>-4 is the correct answer.</em>
To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615
To find the actual percentage, multiply this result by 100.
0.4615 x 100 = 46.15
This percentage rounded is 46%
So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.
I hope this helps!