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marin [14]
3 years ago
9

Calculate the volume of this cone.

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

6m

Step-by-step explanation:

Jjsjsjjs

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What is the volume of a rectangular prism with the dimensions: base 7 2 cm, height 3 2 cm, and length 9 2 cm?
noname [10]

Answer:

Step-by-step explanation:

first do 72times2,32times2,92times2,  then add them all

5 0
3 years ago
Ryan is selling a new computer system that he designed. He spent $200
Neporo4naja [7]

Answer:

Ryan should mark the price as $300.

Step-by-step explanation:

If he wants to markup his price by 50%, you first take 50% of $200 which is $100, then you add it to the original price 200+100= $300

4 0
3 years ago
21 marbles out of N are blue; probability of getting a blue one = 30%
MissTica
Probability=\frac{desired}{total}
0.3=\frac{21}{N}
0.3N=21
N=\frac{21}{0.3}
N=70

There are 70 total marbles. 
4 0
3 years ago
The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assum
Vadim26 [7]

Answer:

a) 0.0951

b) 0.8098

c) Between $24.75 and $27.25.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 26, \sigma = 6, n = 62, s = \frac{6}{\sqrt{62}} = 0.762

(a)

What is the likelihood the sample mean is at least $27.00?

This is 1 subtracted by the pvalue of Z when X = 27. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

1 - 0.9049 = 0.0951

(b)

What is the likelihood the sample mean is greater than $25.00 but less than $27.00?

This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So

X = 27

Z = \frac{X - \mu}{s}

Z = \frac{27 - 26}{0.762}

Z = 1.31

Z = 1.31 has a pvalue of 0.9049

X = 25

Z = \frac{X - \mu}{s}

Z = \frac{25 - 26}{0.762}

Z = -1.31

Z = -1.31 has a pvalue of 0.0951

0.9049 - 0.0951 = 0.8098

c)Within what limits will 90 percent of the sample means occur?

50 - 90/2 = 5

50 + 90/2 = 95

Between the 5th and the 95th percentile.

5th percentile

X when Z has a pvalue of 0.05. So X when Z = -1.645

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 26}{0.762}

X - 26 = -1.645*0.762

X = 24.75

95th percentile

X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{s}

1.645 = \frac{X - 26}{0.762}

X - 26 = 1.645*0.762

X = 27.25

Between $24.75 and $27.25.

3 0
3 years ago
Find the area of a trapezoid with bases 2ft and 3ft and height 1/3 foot. Round your answer to the nearest tenth
amid [387]

Answer:

Area = 5/6 of a foot^2

Step-by-step explanation:

Formula

Area of a trapezoid (formula) = 1/2 (b1 + b2)*h/2

Givens

  • b1 = 2 feet
  • b2 = 3 feet
  • h = 1/3 foot

Solution

Area = 1/2(2 + 3)*1/3

Area = 1/2(5)* 1/3

Area = (1/2 * 1/3) * 5

Area = (1/6) * 5

Area = 5/6


8 0
3 years ago
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