All categories

2 years ago

A taxi charges a flat rate of R10, and an additional cost of 30 cents per kilometer. If you have

Mathematics

1 answer:

Maslowich2 years ago

8 0

Step-by-step explanation:

so, just by getting into the taxi we have to pay R10.

that leaves us 22 - 10 = R12 for the actual trip.

30 cents per kilometer.

so, how many units of 30 cents are there in R12 ? that is the number of kilometers we can go.

R12 = 1200 cent (right ?)

1200 / 30 = 120 / 3 = 40

so, we can travel 40 kilometers for that money.

You might be interested in

Chad buys peanuts in 2 pounds bags. He repackages them into bags that hold 5/6 pound of peanuts. How many 2 pound bags of peanut

zvonat [6]

Think about it this way, that for every 5/6 pound bag you are losing 1/6 and 1/6*12=2 therefore the answer is 12

3 0

2 years ago

A dog that weighs 15 pounds should eat 2 1/8 cups of a certain type of dog food per day. How much of the same type of dog food s

cupoosta [38]

If a 15 lbs dog eats................................17/8 cups of food
a 34 lbs dog will eat,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,? cups

(34 * 17/8)/15=(34*17)/(15*8)=289/15= 19 4/15 cups of food

7 0

3 years ago

Find the missing length of the triangles.

slega [8]

They are both right triangles so we can use the Pythagorean

theorem to solve.

6. B = sqrt(15^2-9^2)

B = 12 mm

7. B = sqrt(26^2-10^2)

B = 24 Cm

5 0

2 years ago

Read 2 more answers

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

What is what is the anwser 34.78x0.12

maks197457 [2]

Answer: 4.1736

Step-by-step explanation:

Simply multiply 34.78 and 0.12 together.

Correct me if I am incorrect

4 0

1 year ago

Read 2 more answers