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3 years ago

a miniature railway increased its prices by 25% to £1.50 how much did it cost to visit the railway before

Mathematics

2 answers:

MAVERICK [17]3 years ago

6 0

The answer is 112.5

type 150 divide by 100 times 25
minus that from 150
and it gives you the answer

nadezda [96]3 years ago

4 0

Let x be the previous price.
So, the equation is the following: $x+0.25x=1.5$
Solve the above equation for x like this:
$x(1+0.25)=1.5\\x1.25=1.5\\x=\frac{1.5}{1.25}=1.2$

The price before was £1.2

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The one-to-one functions g and h are defined as follows

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Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.