A frog 3” long can jump a distance of 18”. If a person 5 feet tall had the ability to jump like a frog, how far could he jump?
1 answer:
You might be interested in
So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>
So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:
Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now we can rewrite this expression as<u> , which is your final answer.</u>