<span>Lets say the 1st die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
2,1
2,2
Now say the 2nd die rolled a 2 -
there would be 2 combinations for which the sum of dice being < 5 :
1,2
2,2
Now we want to count all cases where either dice showed a 2 and sum of the dice was < 5. However note above that the roll (2,2) is counted twice.
So there are three unique dice roll combinations which answer the criteria of at least one die showing 2, and sum of dice < 5:
1,2
2,1
2,2
The total number of unique outcomes for two dice is 6*6=36 .
So, the probability you are looking for is 3/36 = 1/12</span>
Answer:
y = 5^x
Step-by-step explanation:
y= b*(a)^x + c
c could = 1 but then you would not have an exponential function. c = 0 because the graph follows the x axis up until x = -2. Suppose c = 1. The the graph would follow y = 1 up until x = - 2
When x = 0, y = 1 which means that b. If b is anything but 0 or 1 then the y intercept would be stretched to a different place. If be = 0 then y would = 0.
So the graph is of the form y = a^x
Now when x = 0 the graph, the y intercept is y = a^0 or y = 1 So the y intercept is (0,1)
Now the next point is thing to solve for is a.
When x = 1, y = 5 (read the graph)
y = a^x
5 = a^1
5 = a because a^1 is a.
Answer
y = 5^x.
5 = a^1
Ok what else about ms. palmer?
0.0000106 means 1.06 * 10^-5
edited due to a mistake i made.
