Question

Write the equation in standard form. Then factor the left side of the equation. 3x2 + 19x = 14

Answer 1

3x^2+19x-14=0 Standard form
(3x-2)(x+7)=0 Factored

Answer 2

Answer:

Standard form of the equation, $3x^2+19x-14=0$

Factor of the equation is, $(x+7)(3x-2)=0$

Step-by-step explanation:

The standard form of the quadratic equation is given as

$Ax^2+Bx+C = 0$

Given the equation:

$3x^2+19x = 14$

Subtract 14 from both sides we have;

$3x^2+19x-14=0$

⇒The standard form of the equation is,  $3x^2+19x-14=0$

Now, find the factor of the given equation:

$3x^2+19x-14=0$

⇒$3x^2+21x-2x-14=0$

⇒$3x(x+7)-2(x+7) = 0$

⇒$(x+7)(3x-2)=0$

Therefore, the factor of the equation is, $(x+7)(3x-2)=0$