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3 years ago

Given angle 1 = 79, angle 3 = 27, and angle 5 = 82, find the measure of the remaining angles.

Mathematics

1 answer:

sukhopar [10]3 years ago

5 0

Angle 2 = 180 - (angle1 + angle 3 ) = 180-(79+27) = 74°

Angle 3 = angle 4 = 27°

angle 6 = 180-(27+82) = 71°

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Step-by-step explanation:

we are given

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so, let's assume it is equal

$|10x+20|= 10$

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$(10x+20)= 10$

we can solve for x

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$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

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now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

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$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

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We can select any random value from this interval and plug that in inequality

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For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

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