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Hoochie [10]
3 years ago
6

Can someone help me find the slope shown on this line please

Mathematics
1 answer:
Ivan3 years ago
4 0

Answer:

6/2 or 3 would be your slope

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Michael wanted to make another quilt with an area of 42 square feet. What are its possible dimensions of they must be whole numb
Katyanochek1 [597]

The area is the product of the dimensions (length x width).

If the dimensions must be whole numbers and the area is 42 square feet,
then the dimensions can only be . . .

  1-ft  by  42-ft
  2-ft  by  21-ft
  3-ft  by  14-ft
or
  6-ft  by  7-ft .

6-ft  by  7-ft  probably makes the most sense for a quilt.


3 0
3 years ago
I need help asap please it going to 100 points
OLga [1]

Answer:

x ≥ 10

Step-by-step explanation:

So put a filled-in dot on 10 and an arrow going to the right

8 0
3 years ago
Read 2 more answers
Help me pleaseeeeeeeeeeeeeeeee
zalisa [80]

Step-by-step explanation:

j=25+5

j=30

final answer is 30

3 0
3 years ago
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Belinda builds a rectangular prism that is 2 cubes​ long, 3 cubes​ wide, and 2 cubes tall. Each dimension of​ April's rectangula
zepelin [54]

Answer:

96 cubes vol.

Step-by-step explanation:

the volume of Belinda's prism =

2×3×2 = 12 cubes vol.

Each dimension of April's rectangular prism is twice as many cubes as Belinda's prism.

the volume of April's prism =

(2×2)×(2×3)×(2×2)= 4×6×4= 96 cubes vol.

so,

the volume of April's prism = (2)³ times the volume of Belinda's prism

4 0
3 years ago
I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

5 0
2 years ago
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