Write the final equation using the slope-intercept form perpendicular to 3y = x − 4 and passes through the point (−2, 1)
1 answer:
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Answer:
On a coordinate plane, the x-axis is labeled Perimeter of a square, and the y-axis is labeled Side length of a square. A line goes through points (4, 1), (8, 2).
Step-by-step explanation:
Let
x ----> the perimeter of the square
y ---> the side length of the square
Remember that
The perimeter of the square is given by the expression
where
b is the length side of the square
solve for b
That means
A ordered pair in the coordinate plane following the rule
(x,y) -----> (x,x/4)
The y-coordinate is equal to the x-coordinate divided by 4
y=x/4
therefore
On a coordinate plane, the x-axis is labeled Perimeter of a square, and the y-axis is labeled Side length of a square. A line goes through points (4, 1), (8, 2).
Because
For the point (4,1)
substitute in the linear equation the value of x
y=4/4=1 ----> is ok
For the point (8,2)
substitute in the linear equation the value of x
y=8/4=2 ----> is ok
The value of x is 120°
Explanation:
It is given that ABC is a straight line.
Also, ∠CBE = 20° and ∠CAF = 40°
We need to determine the value of ∠DBE
Let ∠DBE = x
Since, ∠CAF and ∠ABD are alternate interior angles.
By the alternate interior angles theorem, "if two parallel lines are cut by a transversal, then the pairs of alternate interior angles are equal".
Thus, ∠CAF and ∠ABD are equal.
Hence, ∠CAF = ∠ABD = 40°
Since, we know that, the angles in a straight line add up to 180°, we have,
∠ABD + ∠DBE + ∠CBE = 180°
Substituting the values, we get,
40° + x + 20° = 180°
Adding, we have,
60° + x = 180°
Subtracting both sides by 60, we have,
x = 120°
Thus, the value of x is 120°
