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skad [1K]
3 years ago
12

Plz help ASAP I need it yo

Mathematics
1 answer:
Natali [406]3 years ago
5 0

Answer:

c!!

Step-by-step explanation:

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Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
xxMikexx [17]

Answer:

The answer is 4 + √15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

\frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }

=  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  -  \sqrt{3} }  \times  \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  +  \sqrt{3} }

=  \frac{ {( \sqrt{5} +  \sqrt{3} ) }^{2} }{( \sqrt{5} -  \sqrt{3} )( \sqrt{5}  +  \sqrt{3})  }

=   \frac{ {( \sqrt{5} )}^{2}  + 2( \sqrt{5} )( \sqrt{3}) +  {( \sqrt{3}) }^{2}  }{ {( \sqrt{5}) }^{2} -  { (\sqrt{3} )}^{2}  }

=  \frac{5 + 2 \sqrt{15} + 3 }{5 - 3}

=  \frac{8 + 2 \sqrt{15} }{2}

= 4 +  \sqrt{15}

3 0
3 years ago
The translation that moves a figure down 4, to the right 2 is
lorasvet [3.4K]
I think it is the 3 on
6 0
3 years ago
Complete the following statement with the number that makes it true.
Step2247 [10]

Answer: 1000

____________________________________________________________

kilogram, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38 ... 1 kg = 1000 grams.

8 0
3 years ago
One-fifth of a number x is less than 8. Find the greatest possible prime number x.
GuDViN [60]
Hello there, I am unable to use the “less than” symbol. Sorry :( .

1/5x "less than" 8
x “Less than” 40

Prime number is 37,41.
Therefore x is 37.
8 0
2 years ago
Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20
ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2,\pm\sqrt{5}

Step-by-step explanation:

Given polynomial is P(x)=x^4-4x^3-x^2+20x-20

To find the zeros equate the given polynomial to zero

ie., P(x)=0

P(x)=x^4-4x^3-x^2+20x-20=0

By using synthetic division we can solve the polynomial:

2_|   1     -4     -1      20      -20

       0      2     -4     -10       20

   _____________________

       1     -2      -5      10      |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

x^3-2x^2-5x+10=0

Again using synthetic division

2_|   1     -2     -5     10      

       0      2      0    -10    

    ______________

       1      0      -5     |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have x^2+0x-5=0

x^2-5=0

x^2=5

x^=\pm\sqrt{5} is a zero of P(x)

Therefore the zeros are 2,2,\pm\sqrt{5}

8 0
3 years ago
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