<span>assume z = ax for simplicity
z(z) = a(ax) = a^2x
let a^2x = 1/16x and solve for a </span>
Answer:

Step-by-step explanation:

so



hope this helped! :)
Answer: 
Step-by-step explanation:
For this exercise it is important to remember the multiplication of signs. Notice that:

In this case you have the following expression given in the exercise:

Then you can follow the steps shown below in order to solve it:
Step 1: You must solve the subtraction of the numbers 0,65 and 3,21. Then:

Step 2: Now you must find the product of the decimal numbers above. In order to do that you must multiply the numbers.
(As you can notice, both are negative, therefore you know that the product will be positive).
Then, you get that the result is the following:

Answer:
Step-by-step explanation:
Given:
Area = 3x^3 - 16x^2 + 31x - 20
Base:
x^3 - 5x
Area of trapezoid, S = 1/2 × (A + B) × h
Using long division,
(2 × (3x^3 - 16x^2 + 31x - 20))/x^3 - 5x
= (6x^3 - 32x^2 + 62x - 40))/x^3 - 5x = 6 - (32x^2 - 92x + 40)/x^3 - 5x = 2S/Bh - Ah/Bh
= 2S/Bh - A/B
= (2S/B × 1/h) - A/B
Since, x^3 - 5x = B
Comparing the above,
A = 32x^2 - 92x + 40
2S/B = 6
Therefore, h = 1
Group together the like terms (plus 2x with 2x) (subtract 10 by 6)
4x+4=36
Move plus four to the other side as a negative
4x=32
Divide both sides by 4
32 divided by 4 is 8
Therefore, x is equal to 8