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Ganezh [65]
3 years ago
11

Order from least to greatest: 50. 2/5, .42

Mathematics
2 answers:
antoniya [11.8K]3 years ago
6 0
.42, 2/5, 50. Is the answer
FinnZ [79.3K]3 years ago
3 0
To make this more simple just do 2 divided 5 and you get .40 so 2/5 is smaller than .42 correct answer will be 2/5, .42
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If sin 0 = 7/25, find csc 0
kipiarov [429]

Answer:

csc(\theta)=\frac{25}{7}

Step-by-step explanation:

We know that:

sin(\theta)=\frac{7}{25}

And we want to find:

csc(\theta)

Remember that there is a trigonometric identity that relates the sin(\theta) function with the csc(\theta) function

csc(\theta)=\frac{1}{sin(\theta)}

Then if sin(\theta)=\frac{7}{25} this means that:

csc(\theta)=\frac{1}{\frac{7}{25}}

Finally:

csc(\theta)=\frac{25}{7}

3 0
3 years ago
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The perimeter of the fig
mr_godi [17]
4+16+10+5+11+6=52yd
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3 years ago
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How to solve #4 and #5
MArishka [77]
If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
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7 0
4 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Pls answer my last one to Rodney sold 45,612 copies of his book and Beth sold 45,612 x one half copies of her book. Which statem
Elden [556K]

Answer:

its most likely b

hope this helps!

6 0
3 years ago
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