Ask question

Ask question

All categories

3 years ago

12

A plot of land is in the shape of a triangle. If one side is x meters, a second side (5x−3) meters, and a third side is ( 7x −

6 ) meters, express the perimeter of the lot as a simplified expression in x.

1 answer:

liubo4ka [24]3 years ago

3 0

Given, the plot is in the shape of triangle.

First side = x meter

Second side = ( 5x-3 )meters

Third side = ( 7x-6 ) meters

Perimeter of triangle is equal to the sum of all the three sides.

Perimeter = $x + (5x-3) + (7x-6)$

Combine like terms by adding all the x terms together and all the constant terms together.

Perimeter = $(x+5x+7x) + ( -3 -6 )$

Perimeter = $13x - 9$ feet ... Answer

You might be interested in

Find the missing side in the similar figures below

Lerok [7]

Answer:

a. 28.8

Step-by-step explanation:

Using the theorem of similarity, the following equation can be generated:

$\frac{x}{12} = \frac{25 + 35}{25}$

Solve for x

$\frac{x}{12} = \frac{60}{25}$

Cross multiply

$x*25 = 60*12$

$25x = 720$

Divide both sides by 25

x = 28.8

5 0

3 years ago

PLS Help! What is the best approximation for the perimeter of a semicircle with a diameter of 12cm? Use 3.14 to approximation pi

In-s [12.5K]

Answer:

A

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Pranked haha hkjkdvhpihigiuaspihgpiaisuhgiuasi free redit

iren2701 [21]

Okay the answer is 69 because 81-2 is 69

6 0

3 years ago

Read 2 more answers

.Bryan was given the equation y= -5x+3. He says the rate of change is 3 and the initial value is -5. Is Bryan correct? If not, c

Mekhanik [1.2K]

Answer:

Correct rate of change is -5; correct initial value is 3.

Step-by-step explanation:

The rate of change is the coefficient of the x term, which here is -5. So Bryan has the rate of change wrong.

The initial value of the function is found by letting x = 0. Here, we get

y = -5(0) + 3, or y = b = 3. The initial value is 3, not -5.

8 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago