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3 years ago

Use the points A (4,4) and B(4,-5). Complete the description of segment AB and find its length.

Mathematics

2 answers:

Scrat [10]3 years ago

5 0

Use the points A(4, 4) and B(4, −5)

(1) (a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same

Here in A(4, 4) and B(4, −5) , the x values are same so the segment AB is a Vertical . The length is the difference between y values ( 4 -(-5)) = 9

Segment AB is a Vertical segment that is 9 units long.

(2) Describe the image of segment AB under the transformation

(x, y) ----> (x, 2y)

A(4, 4) -----> (4, 8)

and B(4, −5) ---> (4, -10)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 8 -(-10)) = 18

The image of segment AB is a Vertical segment that is 18 units long.

(3) Describe the image of segment AB under the transformation

(x, y) ----> (x + 2, y)

A(4, 4) -----> (6, 4)

and B(4, −5) ---> (6, -5)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 4 -(-5)) = 9

The image of AB is a Vertical segment

2 units to the right of the original segment that is

9 units long.

Lemur [1.5K]3 years ago

3 0

I would suggest that you Use the points A(4, 4) and B(4, −5)u

(1) (a) From two points , we will get a vertical line when 'x' values are same and horizontal line segment when 'y' values are same

Here in A(4, 4) and B(4, −5) , the x values are same so the segment AB is a Vertical . The length is the difference between y values ( 4 -(-5)) = 9

Segment AB is a Vertical segment that is 9 units long.

(2) Describe the image of segment AB under the transformation

(x, y) ----> (x, 2y)

A(4, 4) -----> (4, 8)

and B(4, −5) ---> (4, -10)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 8 -(-10)) = 18

The image of segment AB is a Vertical segment that is 18 units long.

(3) Describe the image of segment AB under the transformation

(x, y) ----> (x + 2, y)

A(4, 4) -----> (6, 4)

and B(4, −5) ---> (6, -5)

'x' values are same so line AB is Vertical. The length is the difference between y values ( 4 -(-5)) = 9

The image of AB is a Vertical segment

2 units to the right of the original segment that is

9 units long.

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Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

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$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

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$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

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$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

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miss Akunina [59]

the second option

Step-by-step explanation:

Line CD is parallel to line AB, shown by the arrows in the middle of both of the lines.

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