Laura's uncle donated 120 cans of juice and 90 packs of cheese crackers for the school picnic. Each student is to receive the sa
me number of cans of juice and the same number of packs of crackers. What is the largest number of students that can come to the picnic and share the food equally? How many cans of juice and packs of cheese crackers will each student get? Answer: The largest number of students that can come to the picnic is( ) students. Each student will get ( )cans of juice and( ) packs of cheese crackers.
So we want to know what the largest number that can go into both 90 and 120 aka the Greatest common factor or GCF
so 90=3*3*2*5 120=2*2*3*2*5 the number in common are 3*2*5 if we multiply that out we get 30 so 30 is the maximum number of students so that they all share equally so 90/30=3 so each student gets 3 packs of cheese crackers 120/30=4 so each student gets 4 cans of juice
Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30 What I did next was divide thirty by the number of cracker and also by the number of can of juice.
120÷30= 4
90÷30= 3
So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.
The sum of the residuals is always 0 so the plot will always be centered around the x-axis. An outlier is a value that is well separated from the rest of the data set. An outlier will have a large absolute residual value.
