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borishaifa [10]
4 years ago
9

Laura's uncle donated 120 cans of juice and 90 packs of cheese crackers for the school picnic. Each student is to receive the sa

me number of cans of juice and the same number of packs of crackers. What is the largest number of students that can come to the picnic and share the food equally? How many cans of juice and packs of cheese crackers will each student get?
Answer: The largest number of students that can come to the picnic is( ) students. Each student will get ( )cans of juice and( ) packs of cheese crackers.
Mathematics
2 answers:
Ghella [55]4 years ago
8 0
So we want to know what the largest number that can go into both 90 and 120 aka the Greatest common factor or GCF

so 90=3*3*2*5
120=2*2*3*2*5
the number in common are 3*2*5
if we multiply that out we get 30
so 30 is the maximum number of students so that they all share equally so
90/30=3 so each student gets 3 packs of cheese crackers
120/30=4 so each student gets 4 cans of juice
liubo4ka [24]4 years ago
3 0

Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30  What I did next was  divide thirty by the number of  cracker and also by the number of can of juice.

120÷30= 4

90÷30=  3

So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.


I hope you enjoyed my explanation. :)

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Answer:

M=\left\{\begin{matrix}0.4x &x\leq99 \\ 0.5x &x>100 \\ \end{matrix}\right.

Step-by-step explanation:

<u>Function modeling</u>

Real-life situations often require the help of mathematics to model numerically what happens when the variables involved can change. It could even be used to predict some expected outcomes from those models.

The problem states Janice receives $.40 per pound when he recycles less or equal than 99 pounds of aluminum. If x is the number of recycled pounds, then the amount of money he receives is

M=0.4x

We also know that if he recycles more than 100 pounds of aluminum, the pay increases to $0.5 per pound. In that case, the amount of money is

M=0.5x

This is a case where the function is defined differently depending on the conditions of the input variable x. It's called a piecewise function. The function can be written as

M=\left\{\begin{matrix}0.4x &x\leq99 \\ 0.5x &x>100 \\ \end{matrix}\right.

Note the function is not well constructed because there is a gap for x=100 where M is not defined. If we establish that for 100 pounds the payment is $0.5, then the second piece would include x=100

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Step-by-step explanation:


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A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
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Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

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