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kow [346]
3 years ago
14

Please help!!!!

Mathematics
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

c)  ((6-\sqrt{12} )(6+\sqrt{12} ) = 24

d)    ((3+\sqrt{8} )(3-\sqrt{8} ) = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the binomial expression

          ((6-\sqrt{12} )(6+\sqrt{12} )

Multiply

        ( 36 + 6√12 -6√12 -(√12)²)

    =  ( 36 -12)

   =  24

c)  ((6-\sqrt{12} )(6+\sqrt{12} ) = 24

<u><em>Step(ii):-  </em></u>

Given that the binomial expression

          ((3+\sqrt{8} )(3-\sqrt{8} )

Multiply

 =  9 - 3√8 + 3√8 -(√8)²

=   9 - 8

= 1

d)    ((3+\sqrt{8} )(3-\sqrt{8} ) = 1

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Create three problems that require you to solve each using each of the trig ratios (one problem where you will use sine, one pro
Brilliant_brown [7]
See the attached image for the drawings of the problems. The figures are not to scale. The decimal values in each figure are approximate to one decimal place.

----------------------------------------------

Focus on Figure 1

sin(angle) = opposite/hypotenuse
sin(A) = BC/AC
sin(36) = 13.2/x
x*sin(36) = 13.2
x = 13.2/sin(36)
x = 13.2/0.58778525229248 <<-- make sure calc is in degree mode
x = 22.4571813404936
x = 22.5
This value is approximate (rounded to one decimal place)

----------------------------------------------

Move onto Figure 2

cos(angle) = adjacent/hypotenuse
cos(D) = DE/FD
cos(50) = y/57.4
57.4*cos(50) = y
y = 57.4*cos(50)
y = 57.4*0.64278760968653
y = 36.8960087960069
y = 36.9
This value is approximate (rounded to one decimal place)

----------------------------------------------

Finally, move onto Figure 3

tan(angle) = opposite/adjacent
tan(G) = JH/GH
tan(18) = z/10
10*tan(18) = z
z = 10*tan(18)
z = 10*0.3249196962329
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This value is approximate (rounded to one decimal place)

8 0
3 years ago
I need help on this question please
stepladder [879]

Answer:

The question does not have value of height (in the image)

the barn in shape of a cuboid with a half cylinder.

volume of barn = volume of cuboid + volume of cylinder/2

\text{Volume}_{barn}=lbh+\frac{\pi r^2 l}{2}

here,

2r = b

b=6 m

l=10 m

so, 2r=6. thus, r=3,

\text{Volume}_{barn}=lbh+\frac{\pi r^2 l}{2} \\ \text{Volume}_{barn}= 60\timesh+\pi \times9 \times 5

which approximately,

141.3+60h

for storing all of the hay

141.3+60h≥600

h≥7.644

so..

check if h is less than 7.644, he would not be able to store all of the barn.

mark brainliest please.

8 0
3 years ago
If f(x) = 3x²-4 and g(x) = x+2, find (f - g)(x).
Sergeeva-Olga [200]

Answer:B

Step-by-step explanation:

5 0
2 years ago
Please help me...
nasty-shy [4]

i do believe the correct answer would be letter C. terms, 4mn, m, and 5

hope this helps :)

6 0
4 years ago
Lily and Elsa are both college students.Before mom gave them this months allowance lily had $750 and Elsa had &amp;215.After mom
Drupady [299]

After mom gave each girl an equal amount of money for this months allowance, lily had twice as much money as Elsa. Thus mom gave $ 320 to each girl

<em><u>Solution:</u></em>

Given that Lily and Elsa are both college students

Before mom gave them this months allowance lily had $750 and Elsa had &215

<em><u>Amount (in dollars) with Lily and Elsa already is given as:</u></em>

amount with Lily = $ 750

amount with Elsa = $ 215

After mom gave each girl an equal amount of money for this months allowance, lily had twice as much money as Elsa

Let "x" be the equal amount of money which mom gave to Lily and Elsa

Now amount with Lily and Elsa after mom gave equal amount is:

amount with Lily = amount with Lily already + x

amount with Lily = 750 + x

amount with Elsa = amount with Elsa already + x

amount with Elsa = 215 + x

Given that lily had twice as much money as Elsa

Amount with lily = 2(amount with elsa)

750 + x = 2(215 + x)

750 + x = 430 + 2ax

2x - x = 750 - 430

x = 320

Therefore mom gave $ 320 to each girl

6 0
3 years ago
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