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gtnhenbr [62]
3 years ago
8

Someone please help me!!! I’m stuck and need help!

Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

12

Step-by-step explanation:

These triangles are similar using the AA theroem. This means there sides are in corresponding proportion.

Side AR and Side TE are corresponding. Use this proportion.

\frac{6}{8}

This side the triangle SAR side lengths are 3/4 of side lengths of triangle SET.

We know that RS+ST=21

And that RS=3/4(ST).

\frac{3}{4} x + x = 21

1.75x = 21

x=12.

Side ST is 12

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In the formula C= prn, p stands for
umka21 [38]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the polynomial function of lowest degree with rational real coefficients, and roots -3 and square root of 6?
telo118 [61]

9514 1404 393

Answer:

  f(x) = x³ +3x² -6x -18

Step-by-step explanation:

In order for there to be a root of √6, there must be a factor of (x-√6). In order for there to be rational coefficients, there needs to be another factor of (x+√6) in the minimal polynomial. Then the minimal polynomial with the required roots is ...

  f(x) = (x +3)(x -√6)(x +√6) = (x +3)(x² -6)

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4 0
3 years ago
Solve this for Brainliest!<br><br>See the attachment [Level - GCSE]
madreJ [45]

Answer:

x = 3 + 4\sqrt{3}

Step-by-step explanation:

OPQ is a right angle triangle.

<u>Using Pythagoras</u>

x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0

<u>Using quadratic formula</u>

<u />x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}

x = 3 + 4\sqrt{3} = 9.928(4s.f.)

             OR

x = 3 - 4\sqrt{3} = -3.928(4s.f.) (Length can't be negative)

∴ x = 3 + 4\sqrt{3}

3 0
2 years ago
Read 2 more answers
1. f(x) = x2 - 21<br> f(5)
matrenka [14]

Answer:

x=13

Step-by-step explanation:

if you will substitute the value of f(x) with 5, you will get the following equation:

5=2x-21

2x=26/÷2

x=13

(I didn't know what you ment when you wrote x2, is it x square or 2X)

I really hope it was the second one, cause that's how I solved it.

8 0
3 years ago
Determine whether the sets have a subset relationship. R = {right triangles} O = {obtuse triangles} a) R and O are disjoint. b)
DerKrebs [107]

Answer:

f

Step-by-step explanation:

A right angled triangle has one angle equal to 90°

an obtuse angle triangle has one angle greater tan 90°

a) An o and right-angled triangle btuse angled triangle can have one angle equal.

b) R and O are not equivalent by definition

c)  subset of R and Oare not all triangles as R and O are categories of all triangles. R and O are subset of all triangles

d) Acute triangles have all acute angles. So subset of R and O can't be all acute traingles

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5 0
3 years ago
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