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pashok25 [27]
3 years ago
11

Question is below in photo

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

what about using 20-30-40-5

Step-by-step explanation:

the sequence is that you are skipping ten to get the second nb which is 30 and keep on going on to get 50

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A math book comprises of 2 sections: arithmetic and geometry in the ratio 5:3. How much of each type of content will be needed t
Alex_Xolod [135]
480/8=60

(60*5) : (60*3) = 300:180
4 0
3 years ago
Read 2 more answers
Find the unknown side length x. ​
Ganezh [65]

Answer:

x = \sqrt{65}

Step-by-step explanation:

The altitude of the triangle must equal 4 because it is a right triangle with another leg of 3 and a hypotenuse of 5 (reason is due to the pythagorean theorem)

Therefore, the triangle on the right has legs of 4 and 7 and, again, use the phythagorean theorem to find 'x' (the hypotenuse)

4^{2} + 7^{2} = x^{2}

16 + 49 = x^{2}

65 = x^{2}

x = sq rt 65

6 0
3 years ago
Sustituir. 20c + 15r + 75p + 50e​
AVprozaik [17]

Answer:

8c - 7r + 10p - 20e

Step-by-step explanation:

Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)

Open bracket

20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e

Collect like terms

= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e

= 8c - 7r + 10p - 20e

3 0
3 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
4 years ago
Which of the following binomials is a factor of 22 + 7 −9 ?
Kipish [7]
B i think..............
8 0
3 years ago
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