Which is the most reasonable estimation for the weight of a kitten?
1 answer:
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Answer:
-35,35,0
Step-by-step explanation:
Let's organise our information :
- x+xy²=250y
- x-xy²= -240y
Now let's add them together :
- x+xy²+x-xy²=250y-240y
- 2x=10y
- x=5y ⇒ y= x/5
Let's replace y by x/5 in the first equation :
- x+x*(x/5)²=250*(x/5)
- x+ (x∧3)/25 = 50x
- 49x-(x∧3)/25=0
- x(49-(x²/25))=0
- x=0 or 49-(x²/25)=0
- x=0 or 49= x²/25
- x=0 or x²=1225
- x=0 or x=
or x= -
- x=0 or x=35 or x= -35
so x=[0,35,(-35)]
Answer:
So with the p value obtained and using the significance level given we have
so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.
Step-by-step explanation:
The statistic to test the hypothesis is given by this formula:
Where t follows a t distribution with degrees of freedom
The system of hypothesis on this case are:
Null hypothesis:
Alternative hypothesis:
Or equivalently:
Null hypothesis:
Alternative hypothesis:
Our notation on this case :
represent the sample size for group A
represent the sample size for group B
represent the sample mean for the group A
represent the sample mean for the group B
represent the sample standard deviation for group A
represent the sample standard deviation for group B
And now we can calculate the statistic:
Now we can calculate the degrees of freedom given by:
And now we can calculate the p value using the alternative hypothesis:
So with the p value obtained and using the significance level given we have
so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.