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3 years ago

Find the area of the figure. Assume the figure is made up of triangles.

Mathematics

1 answer:

grigory [225]3 years ago

5 0

S = 2*(1/2 * 7 * 14) + 2* (1/2 * 7 * 7) = 7*14 + 7*7 = 7*(14+7) = 7*21 = 147 sm^2

Number B

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Please help with this question.

8090 [49]

Answer:

2:2

Step-by-step explanation:

8 0

2 years ago

How many books can you get in a storage bin that is 4 feet high and 9 feet long and 11 feet wide

Ugo [173]

Well, this depends on the size of the books. We can find the volume of the bin by using...
V=bh or l x w x h
So, 9 times 11 is 99.
99 times 4 is 396, which is the volume.
You did not specify the size of the books, so all we can say is that the volume of the bin is 396 cubic feet.

4 0

3 years ago

Triangle ABC is similar to triangle DEF. The length of BC is 21cm. The length of DE is 10 cm. The length of EF is 14 cm. What is

Anarel [89]

It's a similar triangle so the ratios of corresponding sides should be equal which means

BC/EF = AB/DE
21/14 = AB/10
AB = 21/14 * 10 = 15 cm

8 0

3 years ago

Read 2 more answers

The ratio of boy campers to the number of girl campers is 8:7. If there are a total of 195 children, how many are boys and how

Luden [163]

$8x-amount\ of\ boys\\7x-amount\ of\ girls\\\\8x+7x=195\\
15x=195\ \ \ |Divide\ by\ 15\\x=13\\\\
8x=8*13=104\\
7x=7*13=91\\\\
\textbf{There\ are\ 104\ boys\ and\ 91\ girls.}$

7 0

3 years ago

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

6 0

2 years ago