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Rama09 [41]
3 years ago
13

A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri

angle with an area of 616 square yards , what would the dimensions of the new triangle be
Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

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Answer:
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nataly862011 [7]
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3 years ago
Find the area of the figure
fiasKO [112]

Step-by-step explanation:

there is one central rectangle :

from (-4, 2) to (2, -2).

that means it dimensions are 6×4 (for x from -4 to +3, for y from +2 to -2).

and then there are 3 additional triangles

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with the leg lengths

(2, -4) to (2, 2) = 6, and (2, 2) to (6, 2) = 4

(-4, -2) to (2, -2) = 6, and (2, -2) to 2, -4) = 2

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the area of the rectangle is

6×4 = 24 square units

the area of the first triangle is

6×4/2 = 3×4 = 12 square units

the area of the second triangle is

6×2/2 = 6 square units

the area of the third triangle is

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so, the total area is

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7 0
2 years ago
If UW = 9x – 9, what is UW in units?
Tju [1.3M]
I will answer this question to the best of my ability, because you have not provided a value of x to plug in.


UW is always equal to 9x-9 or 9(x-1) whenever x is a real number.  By plugging in x, we can get the value.  For example, if x was 4, we plug in x, giving us 9*4-9=36-9=27 units or 9(4-1)=9(3)=27 units
Don't forget to include units when you complete your answer!

Hope this helps!  I did as much as I could!
5 0
3 years ago
3) INITII equation y=-x+ 4<br> equation<br> W10<br> slope (m) = _<br> y-intercept =
vodomira [7]

Answer:

slope (m) = 1 and intercept = -4

Step-by-step explanation:

comparing with Y = mX - c

4 0
3 years ago
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