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Rama09 [41]
3 years ago
13

A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri

angle with an area of 616 square yards , what would the dimensions of the new triangle be
Mathematics
1 answer:
Dimas [21]3 years ago
5 0

Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

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Answer:

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Since adding a positive makes a negative number stay negative, it equals -4.

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Stella [2.4K]

This can be solved by Newton's binomial formula

Tk+1 = (n k) a∧(n-k) b∧k  k+1=7 => k=6, n=11 , a=-3x and b=-2y

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8 0
3 years ago
Read 2 more answers
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maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

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\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

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