Answer:
a: 3
b. 6973568802
Step-by-step explanation:
a₁ = 6 , r = 3 , a₂₀ =?
Result:
a₂₀ = 6973568802
Explanation:
To find a₂₀ we use the formula
aₙ = a₁ · r
^ⁿ⁻¹
In this example we have a₁ = 6 , r = 3 , n = 20. After substituting these values to above
formula, we obtain:
aₙ = a₁ · r
^ⁿ⁻¹
a₂₀ = 6 · 3
^²⁰⁻¹
a₂₀ = 6 · 1162261467
a₂₀ = 6973568802
Answer:
![4\sqrt{\pi}](https://tex.z-dn.net/?f=4%5Csqrt%7B%5Cpi%7D)
Step-by-step explanation:
- The cross section of a sphere is a circle with area
, where radius is given as 4 - The cross section of the cube is a square with area
, where a is side length of square
The circle area = the square area. Thus we have:
![\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}](https://tex.z-dn.net/?f=%5Cpi%20r%5E2%20%3D%20a%5E2%20%5C%5C%5Cpi%284%29%5E2%3Da%5E2%5C%5C16%5Cpi%3Da%5E2%5C%5C%5Csqrt%7B16%5Cpi%7D%3Da%5C%5C%20a%3D%5Csqrt%7B16%7D%20%5Csqrt%7B%5Cpi%7D%20%5C%5Ca%3D4%5Csqrt%7B%5Cpi%7D)
Answer:
One solution
Step-by-step explanation:
Lets solve it for b
3b= -6a+12
3b= 6a-12
Simplifying
b= -2a+4
b= 2a+4
Both have same slope and intercept hence both lines are going to intersect at one point. So the equations are having one solution.
The maximized value of the function is (c) 119/2
<h3>Maximization problem</h3>
Maximization problems are used to determine the optimal solution of a linear programming model
<h3>Objective function</h3>
The objective function is given as:
![P(x,y) = 11x + 10y](https://tex.z-dn.net/?f=P%28x%2Cy%29%20%3D%2011x%20%2B%2010y)
<h3>Constraints</h3>
The constraints are given as:
![22x + 2y \le 68](https://tex.z-dn.net/?f=22x%20%2B%202y%20%5Cle%2068)
![8x + 16y \le 68](https://tex.z-dn.net/?f=8x%20%2B%2016y%20%5Cle%2068)
![x,y\ge 0](https://tex.z-dn.net/?f=x%2Cy%5Cge%200)
<h3>Graph</h3>
See attachment for the graph of the constraints
From the graph, the optimal solution is: (2.83, 2.83)
So, the maximized value is:
![P(x,y) = 11x + 10y](https://tex.z-dn.net/?f=P%28x%2Cy%29%20%3D%2011x%20%2B%2010y)
![P =11 \times 2.833 + 10 \times 2.833](https://tex.z-dn.net/?f=P%20%3D11%20%5Ctimes%202.833%20%2B%2010%20%5Ctimes%202.833)
![P =59.493](https://tex.z-dn.net/?f=P%20%3D59.493)
Approximate
![P =59.5](https://tex.z-dn.net/?f=P%20%3D59.5)
Rewrite as a fraction
![P =\frac{119}{2}](https://tex.z-dn.net/?f=P%20%3D%5Cfrac%7B119%7D%7B2%7D)
Hence, the maximized value of the function is (c) 119/2
Read more about maximization problem at:
brainly.com/question/16826001
Answer:
ok
Step-by-step explanation:
thank you hjghvcfhjkbvdddjknbchkbb