PLease help asap!!! :)

) Evaluate: 4+8= 2 (6 - 3) 16 33 25 18 Done HURRY

dlinn [17]

I got the answer six. I’m not sure how those other answers are possible.

5 0

3 years ago

If {4x-3y=17 and 2x-5y=-11 then y=?

anyanavicka [17]

You need to solve this "system of linear equations." In other words, find a point (x,y) that satisfies both 4x-3y=17 and 2x-5y=-11.

Try solution by elimination. Multiply the 2nd equation by -2 to obtain -4x+5y=22. Add this result to the 1st equation. I'd suggest you write this out to see what is happening.

4x-3y=17

-4x+10y=22
----------------
7y=39. Solving for y, we get y=39/7 (a rather awkward fraction).

Now find x. To do this, substitute 39/7 for y in either of the given equations. Solve the resulting equation for x.

Write your solution in the form (x, y): ( ? , 39/7).

3 0

3 years ago

Which is one of the solutions to the equation 2x^2 - x - 4 = 0

Alex73 [517]

Answer:

$x_{1}=\frac{1+\sqrt{33} }{4}\\x_{2}=\frac{1-\sqrt{33} }{4}$

Step-by-step explanation:

Using quadratic formula

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2 b=-1 c=-4, we have:

$x_{1}=\frac{+1+\sqrt{-1^{2}-4*2*-4} }{2*2}\\\\x_{2}=\frac{+1-\sqrt{-1^{2}-4*2*-4} }{2*2}$

Finally, we have two solutions:

$x_{1}=\frac{1+\sqrt{33} }{4}\\\\x_{2}=\frac{1-\sqrt{33} }{4}$

5 0

4 years ago

Simplify the given expression below 4/3-2i

ANTONII [103]

So-called simplifying, really means, "rationalizing the denominator", which is another way of saying, "getting rid of that pesky radical in the bottom"

$\bf \cfrac{4}{3-2i}\cdot \cfrac{3+2i}{3+2i}\impliedby \textit{multiplying by the conjugate of the bottom}
\\\\\\
\cfrac{4(3+2i)}{(3-2i)(3+2i)}\implies \cfrac{4(3+2i)}{3^2-(2i)^2}\implies \cfrac{4(3+2i)}{3^2-(4i^2)}\\\\
-------------------------------\\\\
recall\qquad i^2=-1\\\\
-------------------------------\\\\
\cfrac{4(3+2i)}{3^2-(4\cdot -1)}\implies \cfrac{4(3+2i)}{9+4}\implies \cfrac{12+8i}{13}\implies \cfrac{12}{13}+\cfrac{8}{13}i$

4 0

3 years ago

Read 2 more answers

Answer correctly please

Paul [167]

Answer:

$\$272,49$

Step-by-step explanation:

7. $\displaystyle /text{The answer makes sense because since the depreciation rate is 15%, we know that we need to use the "exponential decay" formula.}$

6. $\displaystyle /text{After a depreciation rate of 15% for the past 8 years, the stock is now worth approximately $272,49.}$

5. $\displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49$

4. $\displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]$

3. $\displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0$

2. $\displaystyle /text{How much is the stock worth after a depreciation rate of 15% per year?}$

1. $\displaystyle /text{initial amount: $1000, a depreciation rate of 15%, and a time period of 8 years}$

I am joyous to assist you anytime.

5 0

3 years ago