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3 years ago

PLease help asap!!! :)

Mathematics

1 answer:

snow_tiger [21]3 years ago

3 0

7,3,10 are the answers

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Whats the value of x?

Nutka1998 [239]

Answer:

x = 8 units, measure of angle AFE = 60 degrees, measure of angle CFD = 60 degrees

Step-by-step explanation:

Finding x:

You know all three of the given measures add up to 180 because they are on the same side of the line. Write an equation and solve for x.

6x + 2 + 8x + 6 + 7x + 4 = 180

21x = 168 --> x = 8

Angle AFE:

Substitute the value of x in the given measure.

7x + 4 = 7*8 + 4 = 56 + 4 = 60

Measure of angle CFD:

Angle AFE is it's vertical angle, so their measures (60 degrees) are equal.

7 0

3 years ago

1. If I can buy 3 pounds of grapes for $7.00, how much will 12 pounds cost?

Sladkaya [172]

7*4= $28 (hope this help!)

6 0

2 years ago

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CASLAN UR HERE 56+6x567890-9

sammy [17]

Answer: 35, 209, 171

Step-by-step explanation: hope i helped

4 0

3 years ago

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How do i find the area for number 4?

ankoles [38]

<h3>Answer: 41 cm^2</h3>

Explanation:

Form a horizontal line as shown below (see attached image). This forms 2 separate smaller rectangles

The bottom rectangle has area of 4*8 = 32 cm^2
The top rectangle has area of 3*3 = 9 cm^2

The total area is therefore 32+9 = 41 cm^2

You can say "square cm" or "sq cm" in place of the "cm^2".

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3 years ago

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The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar

mafiozo [28]

Answer:

$Ratio = \frac{R^2 - r^2 }{ r^2}$

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

$Area = \frac{\theta}{360}\pi r^2$

For the inner circle

$r \to radius$

The sector of the inner circle has the following area

$A_1 = \frac{\theta}{360}\pi r^2$

For the whole circle

$R \to Radius$

The sector of the outer sector has the following area

$A_2 = \frac{\theta}{360}\pi (R^2 - r^2)$

So, the ratio of the outer sector to the inner sector is:

$Ratio = A_2 : A_1$

$Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2$

Cancel out common factor

$Ratio = R^2 - r^2 : r^2$

Express as fraction

$Ratio = \frac{R^2 - r^2 }{ r^2}$

6 0

3 years ago